A screw jack of pitch 5 mm is used to lift the tyre of a vehicle of load 200 kg with the help of a handle of length 0.5 m. Neglecting the friction force between screw and nut of the jack, the least force required to raise the load is
Text Solution
Verified by ExpertsThe correct answer is:
C
Work done in one rotation = work done against gravity
i.e., F × 2 π π × 
= 200 × 10 × 5 × 10 -3
(F × 2 π π l = (mg) × pitch)
F = 
= 3.18 N
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